June 22, 2024
6 min read
The notice for the June 2024 session of the CSIR NET test was issued by the National Testing Agency (NTA) on 1 May 2024. The CSIR NET Application Form 2024 is now accessible on the official website of the NTA. The Council of Scientific and Industrial Research administers the National Eligibility Test (NET) twice a year to assess applicants' eligibility for Junior Research Fellowships (JRFs) and Lecturer posts.
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Table of content
The National Testing Agency (NTA) administers the Council of Scientific and Industrial Research National Eligibility Test (CSIR NET) biannually on behalf of the Council of Science and Industrial Research (CSIR) under the Ministry of Science and Technology. The CSIR NET Exam 2024 is administered biannually in an online format, offering people the chance to pursue a PhD or aspire to become assistant professors.
The National Testing Agency (NTA) has issued the CSIR NET June 2024 Notification, along with the CSIR NET Application Form 2024, on May 1, 2024. Candidates who are interested in taking the CSIR UGC NET 2024 test may register by visiting the official website, csirnet.nta.ac.in, between May 1 and May 21, 2024.
Events |
Dates |
CSIR NET notification 2024 |
May 1, 2024 |
CSIR NET 2024 application form fill up start date |
May 1, 2024 |
The last date to fill up CSIR NET application form 2024 |
May 27, 2024 (Extended) |
Online CSIR NET application fee payment last date |
May 27, 2024 (Upto 11:50 PM) |
CSIR UGC NET application form online correction window |
May 29 to 31, 2024 |
CSIR NET city intimation slip date |
June 15, 2024 |
CSIR NET 2024 admit card date |
To be notified |
CSIR NET exam date 2024 |
New date to be announced |
The release date of the CSIR NET provisional answer key |
To be notified |
The challenging window of provisional answer key of CSIR NET 2024 |
To be notified |
CSIR NET 2024 final answer key date |
To be notified |
CSIR NET result date 2024 |
To be notified |
CSIR NET 2024 Overview | |
Particulars | Information |
Exam Name | CSIR NET 2024 |
Exam Conducting Body | National Testing Agency |
Full Exam Name | Council of Scientific and Industrial Research National Eligibility Test |
Frequency of Conduct | Twice a year |
Mode of Application | Online |
Application Fee (General) | Rs 1150 (Online) |
Counselling Mode | Online |
Exam Mode | Online |
Duration of Exam | 3 Hours |
Official Website | csirnet.nta.nic.in |
Prospective candidates aiming to take the CSIR NET 2024 should meticulously examine the examination structure in order to comprehend its prerequisites. Applicants are required to possess knowledge of the specific marking system and allocation of marks for each topic in the forthcoming CSIR NET Exam 2024. The Council of Scientific and Industrial Research Exam 2024 will be conducted over the internet and will have a duration of three hours. Applicants must respond to multiple-choice questions of an objective nature. To get more comprehensive information, please consult the table provided below.
CSIR NET 2024 Exam Pattern | |
Exam Pattern | Details |
Sections | Part A, B, and C |
Part A (Common to all subjects) | Maximum of 20 questions, Candidates answer 15 questions (2 marks each), Total marks: 30 out of 200, Assesses teaching/research aptitude, reasoning ability, comprehension skills, divergent thinking, and general awareness. |
Parts B and C (Subject-based) | Based on candidates’ chosen subjects: Earth, Atmospheric, Ocean and Planetary Sciences, Chemical Sciences, Life Sciences, Mathematical Sciences, and Physical Sciences. |
Exam Duration | Three hours |
Total Marks | 200 |
Negative Marking | – 25% for each incorrect answer (33% for a few parts). |
Subject Variation | Exam pattern varies for each of the five subjects. |
See Also :
The CSIR NET 2024 cutoff will be published online by the National Testing Agency on the website csirnet.nta.ac.in. Exam candidates may get the CSIR NET cutoff for 2024 on the official website. The CSIR NET 2024 cutoff will be published independently for the Junior Research Fellowship (JRF) and Lectureship (NET). The applicant must get a score that is equal to or higher than the CSIR NET 2024 cutoff in order to qualify for the test. The CSIR NET cutoff will be issued in two separate portions, one based on categories and the other based on disciplines.
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